-[10z-(14z+2)]=2+(3z+10)

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Solution for -[10z-(14z+2)]=2+(3z+10) equation:


Simplifying
-1[10z + -1(14z + 2)] = 2 + (3z + 10)

Reorder the terms:
-1[10z + -1(2 + 14z)] = 2 + (3z + 10)
-1[10z + (2 * -1 + 14z * -1)] = 2 + (3z + 10)
-1[10z + (-2 + -14z)] = 2 + (3z + 10)

Reorder the terms:
-1[-2 + 10z + -14z] = 2 + (3z + 10)

Combine like terms: 10z + -14z = -4z
-1[-2 + -4z] = 2 + (3z + 10)
[-2 * -1 + -4z * -1] = 2 + (3z + 10)
[2 + 4z] = 2 + (3z + 10)

Reorder the terms:
2 + 4z = 2 + (10 + 3z)

Remove parenthesis around (10 + 3z)
2 + 4z = 2 + 10 + 3z

Combine like terms: 2 + 10 = 12
2 + 4z = 12 + 3z

Solving
2 + 4z = 12 + 3z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-3z' to each side of the equation.
2 + 4z + -3z = 12 + 3z + -3z

Combine like terms: 4z + -3z = 1z
2 + 1z = 12 + 3z + -3z

Combine like terms: 3z + -3z = 0
2 + 1z = 12 + 0
2 + 1z = 12

Add '-2' to each side of the equation.
2 + -2 + 1z = 12 + -2

Combine like terms: 2 + -2 = 0
0 + 1z = 12 + -2
1z = 12 + -2

Combine like terms: 12 + -2 = 10
1z = 10

Divide each side by '1'.
z = 10

Simplifying
z = 10

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